๐Ÿ—๏ธ Algorithm/๐ŸŸฉ ๋ฐฑ์ค€

[๋ฐฑ์ค€] (Python) 5585๋ฒˆ _๊ฑฐ์Šค๋ฆ„๋ˆ

Dbswnstjd 2022. 2. 17. 16:02

https://www.acmicpc.net/problem/5585

 

5585๋ฒˆ: ๊ฑฐ์Šค๋ฆ„๋ˆ

ํƒ€๋กœ๋Š” ์ž์ฃผ JOI์žกํ™”์ ์—์„œ ๋ฌผ๊ฑด์„ ์‚ฐ๋‹ค. JOI์žกํ™”์ ์—๋Š” ์ž”๋ˆ์œผ๋กœ 500์—”, 100์—”, 50์—”, 10์—”, 5์—”, 1์—”์ด ์ถฉ๋ถ„ํžˆ ์žˆ๊ณ , ์–ธ์ œ๋‚˜ ๊ฑฐ์Šค๋ฆ„๋ˆ ๊ฐœ์ˆ˜๊ฐ€ ๊ฐ€์žฅ ์ ๊ฒŒ ์ž”๋ˆ์„ ์ค€๋‹ค. ํƒ€๋กœ๊ฐ€ JOI์žกํ™”์ ์—์„œ ๋ฌผ๊ฑด์„ ์‚ฌ

www.acmicpc.net

ํ’€์ด

์•Œ๊ณ ๋ฆฌ์ฆ˜ : ๊ทธ๋ฆฌ๋”” ์•Œ๊ณ ๋ฆฌ์ฆ˜

# ๋ฐฑ์ค€ 5585๋ฒˆ ๋ฌธ์ œ - ๊ฑฐ์Šค๋ฆ„๋ˆ
n = int(input())
val = 1000 - n
# 500, 100, 50, 10, 5, 1
coin = [500, 100, 50, 10, 5, 1]
count = 0
for i in coin:
    count += (val // i)
    val = val % i
print(count)

1. ๊ฑฐ์Šค๋ฆ„๋ˆ์˜ ๊ฐฏ์ˆ˜๋ฅผ ์„ธ๊ธฐ ์œ„ํ•ด 1000์—”์—์„œ ๋‚ธ ๋ˆ์„ ๋บ€ ํ›„ val์— ์ €์žฅ

 

2. ๊ฑฐ์Šค๋ฆ„๋ˆ์ด 500, 100, 50, 10, 5, 1์—”์ด ์žˆ์œผ๋ฏ€๋กœ coin์˜ ๋ฆฌ์ŠคํŠธ์— ๋ชจ๋‘ ์ €์žฅ

 

3. for๋ฌธ ์•ˆ์—์„œ count ์—๋Š” val์„ ๊ฑฐ์Šค๋ฆ„๋ˆ์œผ๋กœ ๋‚˜๋ˆˆ ๊ฐ’์„ ์ €์žฅ ํ›„ ๋”ํ•˜๊ธฐ

 

4. val ์€ ๋‚˜๋จธ์ง€ ๊ฐ’์„ ์ €์žฅ

 

5. count ์ถœ๋ ฅ