๐Ÿ—๏ธ Algorithm/๐ŸŸฉ ๋ฐฑ์ค€

๐ŸŸฉ [๋ฐฑ์ค€] [Python] [Gold4] 1753๋ฒˆ_์ตœ๋‹จ๊ฒฝ๋กœ

Dbswnstjd 2023. 4. 16. 17:36

๋ฌธ์ œ

https://www.acmicpc.net/problem/1753

 

1753๋ฒˆ: ์ตœ๋‹จ๊ฒฝ๋กœ

์ฒซ์งธ ์ค„์— ์ •์ ์˜ ๊ฐœ์ˆ˜ V์™€ ๊ฐ„์„ ์˜ ๊ฐœ์ˆ˜ E๊ฐ€ ์ฃผ์–ด์ง„๋‹ค. (1 ≤ V ≤ 20,000, 1 ≤ E ≤ 300,000) ๋ชจ๋“  ์ •์ ์—๋Š” 1๋ถ€ํ„ฐ V๊นŒ์ง€ ๋ฒˆํ˜ธ๊ฐ€ ๋งค๊ฒจ์ ธ ์žˆ๋‹ค๊ณ  ๊ฐ€์ •ํ•œ๋‹ค. ๋‘˜์งธ ์ค„์—๋Š” ์‹œ์ž‘ ์ •์ ์˜ ๋ฒˆํ˜ธ K(1 ≤ K ≤ V)๊ฐ€

www.acmicpc.net

ํ’€์ด

# ๋ฐฑ์ค€ 1753๋ฒˆ ๋ฌธ์ œ - ์ตœ๋‹จ๊ฒฝ๋กœ
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**6)

import heapq

n, m = map(int, input().split())

k = int(input())

INF = int(1e9)

graph = [[] * (n+1) for _ in range(n+1)]
distance = [INF] * (n+1)

for _ in range(m):
    a, b, c = map(int, input().split())
    graph[a].append((b, c))


def dijkstra(start):
    q = []
    heapq.heappush(q, (0, start))
    distance[start] = 0

    while q:
        dist, now = heapq.heappop(q)
        if distance[now] < dist:
            continue
        for i in graph[now]:
            cost = dist + i[1]
            if cost < distance[i[0]]:
                distance[i[0]] = cost
                heapq.heappush(q, (cost, i[0]))

dijkstra(k)

for i in range(1, n+1):
    if distance[i] == INF:
        print("INF")
    else:
        print(distance[i])

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