๐Ÿ—๏ธ Algorithm/โฌ› ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

[Programmers] [Python] Level1_2016

Dbswnstjd 2022. 3. 7. 01:30

https://programmers.co.kr/learn/courses/30/lessons/12901#

 

์ฝ”๋”ฉํ…Œ์ŠคํŠธ ์—ฐ์Šต - 2016๋…„

2016๋…„ 1์›” 1์ผ์€ ๊ธˆ์š”์ผ์ž…๋‹ˆ๋‹ค. 2016๋…„ a์›” b์ผ์€ ๋ฌด์Šจ ์š”์ผ์ผ๊นŒ์š”? ๋‘ ์ˆ˜ a ,b๋ฅผ ์ž…๋ ฅ๋ฐ›์•„ 2016๋…„ a์›” b์ผ์ด ๋ฌด์Šจ ์š”์ผ์ธ์ง€ ๋ฆฌํ„ดํ•˜๋Š” ํ•จ์ˆ˜, solution์„ ์™„์„ฑํ•˜์„ธ์š”. ์š”์ผ์˜ ์ด๋ฆ„์€ ์ผ์š”์ผ๋ถ€ํ„ฐ ํ† ์š”์ผ๊นŒ

programmers.co.kr

ํ’€์ด

# ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค 1๋‹จ๊ณ„ - 2016
def solution(a, b):
    date = ['FRI', 'SAT', 'SUN', 'MON', 'TUE', 'WED', 'THU']
    month = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
    answer = date[(sum(month[:a-1])+b-1)%7] 
    print(type(answer))
    return answer

 

datetime์„ ์ด์šฉํ•˜์—ฌ ํ’€์ด

import datetime

def getDayName(a,b):
    t = 'MON TUE WED THU FRI SAT SUN'.split()
    return t[datetime.datetime(2016, a, b).weekday()]