๐๏ธ Algorithm/๐ฉ ๋ฐฑ์ค
๐ฉ [๋ฐฑ์ค] [Python] [Gold4] 1753๋ฒ_์ต๋จ๊ฒฝ๋ก
Dbswnstjd
2023. 4. 16. 17:36
๋ฌธ์
https://www.acmicpc.net/problem/1753
1753๋ฒ: ์ต๋จ๊ฒฝ๋ก
์ฒซ์งธ ์ค์ ์ ์ ์ ๊ฐ์ V์ ๊ฐ์ ์ ๊ฐ์ E๊ฐ ์ฃผ์ด์ง๋ค. (1 ≤ V ≤ 20,000, 1 ≤ E ≤ 300,000) ๋ชจ๋ ์ ์ ์๋ 1๋ถํฐ V๊น์ง ๋ฒํธ๊ฐ ๋งค๊ฒจ์ ธ ์๋ค๊ณ ๊ฐ์ ํ๋ค. ๋์งธ ์ค์๋ ์์ ์ ์ ์ ๋ฒํธ K(1 ≤ K ≤ V)๊ฐ
www.acmicpc.net
ํ์ด
# ๋ฐฑ์ค 1753๋ฒ ๋ฌธ์ - ์ต๋จ๊ฒฝ๋ก
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10**6)
import heapq
n, m = map(int, input().split())
k = int(input())
INF = int(1e9)
graph = [[] * (n+1) for _ in range(n+1)]
distance = [INF] * (n+1)
for _ in range(m):
a, b, c = map(int, input().split())
graph[a].append((b, c))
def dijkstra(start):
q = []
heapq.heappush(q, (0, start))
distance[start] = 0
while q:
dist, now = heapq.heappop(q)
if distance[now] < dist:
continue
for i in graph[now]:
cost = dist + i[1]
if cost < distance[i[0]]:
distance[i[0]] = cost
heapq.heappush(q, (cost, i[0]))
dijkstra(k)
for i in range(1, n+1):
if distance[i] == INF:
print("INF")
else:
print(distance[i])
๋ค์ต์คํธ๋ผ ์๊ณ ๋ฆฌ์ฆ์ ์ฌ์ฉํ์๋ค.